0=9x^2-19x-10

Solution for 0=9x^2-19x-10 equation:

0=9x^2-19x-10

We move all terms to the left:

0-(9x^2-19x-10)=0

We add all the numbers together, and all the variables

-(9x^2-19x-10)=0

We get rid of parentheses

-9x^2+19x+10=0

a = -9; b = 19; c = +10;
Δ = b2-4ac
Δ = 192-4·(-9)·10
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{721}}{2*-9}=\frac{-19-\sqrt{721}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{721}}{2*-9}=\frac{-19+\sqrt{721}}{-18}
$